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A given sample of `N_(2)O_(4)` in a closed vessel shows `20%` dissociation in `NO_(2)` at `27^(@)C` and `760 "torr"`. The sample is now heated upto `127^(@)C` and the analysis of mixture shows `60%` dissociation at `127^(@)C`. The density of the equilibrium mixture (in `g//litre`) at `27^(@)C` is :A. `3.1`B. `4.2`C. `2.1`D. `3.7` |
Answer» At `300 K`, `K_(p)=K_(c)(RT)^(Deltan)` `:. K_(c)=(0.165)/(0.0821xx300)=6.7xx10^(-3)` Also `K_(c)=(((0.4a)/(V))^(2))/(((0.8a)/(V)))=6.7xx10^(-3)` `:. (a)/(V)=(6.7xx10^(-3))/(0.2)=0.0335` Also density of mixture at `300 K` `=(1.2axx76.67)/(V)` (`d=(w)/(V)`) `=1.2xx0.0335xx76.67` `=3.082 g//litre` |
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