1.

A glass lens is coated on one side with a thin film of magnesium fluoride (MgF_(2))to reduce reflection from the lens surface (Fig. 2.26). The Index of refraction of MgF_(2) is 1.38, that of the glass is 1.50. What is the least coating thickness that eliminates (via interference) the reflections at the middle of the visible specturm (lambda = 550nm)? Assume that the light is approxmately perpendicular to the lens surface.

Answer»

112.4nm
78.2 nm
99.64 nm
225 nm

Solution :C
For destructive interference,
`2n_(1)t_(MIN)=lambda/2`
`:. t_(min)=550/(4xx1.38)=99.64nm.`


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