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A glass of refraction index 1.5 and radius-.1 m has a small bubbl inside at a distance of 0.01 m from the centre. Where will the mark appear to the observer when viewed along the diameter containing the bubble? |
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Answer» Solution :`(n_(1))/(u ) + ( n_(2))/(V) = ( n_(1) -n_(2))/( R) ` or `( N)/( u ) + ( 1)/( v) = ( n+1)/( R )` `(1.5) /(0.09) + ( 1)/( v) = ( 1.5-1)/( 0.1)` `16.66 + ( 1)/( v) = 5` `(1)/( v) = 5-16.66 = - 11.66 v = -0.0857m` |
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