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A glass surface is coated by an oil film of uniform thickness 1.00xx10^-4cm. The index of refraction of the oil is 1.25 and that of the glass is 1.50. Find the wavelengths of light in the visible region (400nm-750nm) which are completely transmitted by the oil film under normal incidence. |
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Answer» `d=1xx10^-4cm` `10^-6m` `mu_(oil)=1.25 and mu` `=1.50` `LAMDA(2mud)/((n+1/2)) `=(2xx10^-6xx(1.25)xx2)/((2n+1))` `=(5xx10^-6m)/(2n+1)` `RARR lamda=(5000nm)/(2n+1)` ` For the wavelength is the region (400nm-750 nm) when n=3, `lamda=5000-(2xx3+1) `5000/7=714.3` when n=4 `lamda=5000/(2xx4+1)` `=5000/9=555.6nm` `when n=5 lamda=5000/(2x5+1)` =5000/11=454.5nm` |
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