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A glass tube of `1.0 m` length is filled with water . The water can be drained out slowly at the bottom of the tube . If a vibrating tuning fork of frequency `500 c//s` is brought at the upper end of the tube and the velocity of sound is `330 m//s`, then the total number of resonances obtained will beA. 4B. 3C. 2D. 1 |
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Answer» Correct Answer - B Wavelength, `lamda=("Velocity")/("Frequency")=(330ms^(-1))/(500ms^(-1))=0.66m` The resonance occurs at `lamda/4,(3lamda)/4,(5lamda)/4,(7lamda)/4,….. i.e., at 0.165 m, 0.495 m, 0.825 m, 1.155 m. As the length of the tube is only 1.0 m, hence 3 resonances will be observed. |
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