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A glass tube of radius r is dipped vertically into a container of mercury of density `rho` with its lower end at a depth h below the mercury surface . If S is the surface tension of mercury, what must be the gauge pressure of air in the tube to blow a hemispherical bubble at the lower end? |
Answer» Gauge pressure in te hemispherical eair bubble formed at the end of the glass tube in mercury is P = excess of pressure + Pressure due to h column of mercury `=(2S)/( r ) + h rho g`. |
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