InterviewSolution
Saved Bookmarks
| 1. |
Calculate the specific heat capacity at constant volume for a gas. Given specific heat capacity at constant pressure is `6.85 cal mol^(-1) K^(-1), R = 8.31 J mol^(-1)K^(-1)`. `J - 4.18 J cal^(-1)`. |
|
Answer» Here, `C_(p) = 6.85 cal mol^(-1)K^(-1)`, `R=8.31 mol^(-1) K^(-1)` `:. R = 8.31/4.18 cal mol^(-1)K^(-1)` `C_(V)=C_(p) - R = 6.85 - 1.988` `=4.862 cal mol^(-1)K^(-1)`. |
|