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The upper end of a wire of radius 4 mm and length 100 cm is clamped and its other end is twisted through an angle of `30^@`. Then angle of shear isA. `12^(@)`B. `1.2^(@)`C. `0.12^(@)`D. `0.012^(@)` |
Answer» Correct Answer - C Angle of twist at free end `=30^(@)=(30)/(180)xxpi` rad `=(pip)/(6)` rad Displacement of the free surface, `Delta L=(2pi r)/(2 pi)xx(pi)/(6)=(pi r)/(6)=(pixx0.4)/(6)cm` Angle of shear or shearing strain `=(Delta L)/(L)` `=(pixx0.4)/(6xx100)` rad. `=(pixx0.4)/(6xx100)xx(180)/(pi)` degree `=0.12^(@)` |
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