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A glass wedge of angle 0.01 radian is illuminated by monochromatic light of wavelength 6000 Å falling normally on it. At what distance from the wedge will 10th dark fringe be observed by reflected light ? (mu = 1.5) : |
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Answer» `0.1 MM` `lambda = 6000 Å = 6000 xx 10^(-10) m` `x_(n) = ? , n = 10` Now `t = x_(n) theta= x_(n) xx 0.01`...(i) `mu = 1.5` Condition for maxima is `2 mu t = n lambda` `t = (n lambda)/(2MU) = (10 xx 6000 xx 10^(-10))/(2 xx 15) = 2 mu m`...(ii) From EQN.(i), `x_(n) = (t)/(theta) = (2)/(0.01) = 200 mu m = 0.2 mm` `THEREFORE x_(n) = 0.2 mm`. |
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