A golfer standing on the ground hits a ball with a velocity of 52 m/s at an angle theta above the horizontal if tan theta=(5)/(12) find the time for which the ball is at least 75m above the ground? (g=10 m//s^(2))

A golfer standing on the ground hits a ball with a velocity of 52 m/s

1.	A golfer standing on the ground hits a ball with a velocity of 52 m/s at an angle theta above the horizontal if tan theta=(5)/(12) find the time for which the ball is at least 75m above the ground? (g=10 m//s^(2))
Answer» Solution :`v_(y)= sqrt(u_(y)^(2)-2gy) ` `=sqrt(52xx52xx(5xx5)/(13xx13)-2xx10xx15)= sqrt(16xx25-300)=10` `Delta =(2u_(y))/(10)=(2XX10)/(10)=2s`

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A golfer standing on the ground hits a ball with a velocity of 52 m/s at an angle theta above the horizontal if tan theta=(5)/(12) find the time for which the ball is at least 75m above the ground? (g=10 m//s^(2))

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