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A goods train starts from station A to the station B and at the same time a passenger train starts from station B to station A. After meeting they reached their destination in 9 hours and4 hours respectively. Find the ratio of their speed. |
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Answer» 680 Step-by-step explanation: ANSWER Solution: Given Train starts at the same time. Hence, Time REMAINS constant. Speed of Train 'T1' be 'S1' = 40 km\hr Speed of Train 'T2' be 'S2' = 45 km\hr Let X be the distance at which trains meet. Train T2 travels X+40 km more than Train T1 According to the formula. Speed= Time Distance
Time= 45 X+40
Time= 40 X
From above two equations. 40 X
= 45 X+40
45×X=40×X+40×40 5×X=1600 =320 km Distance between two Stations = Distance at which train T1 meet + Distance at which Train T2 meet + Distance train T2 travels = 320+320+40 = 680 |
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