A gram molecule of gas at `27^(@)C` expands isothermally untill its volume is doubled. Find the amount of work done and heat absorbed. Take `R=8.31J mol e^(-1) K^(-1)`.

A gram molecule of gas at `27^(@)C` expands isothermally untill its vo

1.	A gram molecule of gas at `27^(@)C` expands isothermally untill its volume is doubled. Find the amount of work done and heat absorbed. Take `R=8.31J mol e^(-1) K^(-1)`.
Answer» Here, `T= 27^(@)C= 27+273= 300 K, V_(2)= 2V_(1)` `W=2.3026RT "log"_(10)(V_(2))/(V_(1)) 2.3026xx8.31xx300 log_(10) 2= 2.3026xx8.31xx300xx0.3010` `W=1.727xx10^(3) "joule"` Amount of heat absorbed `=(1.727xx10^(3))/(4.2)cal. 411.4 cals`

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A gram molecule of gas at `27^(@)C` expands isothermally untill its volume is doubled. Find the amount of work done and heat absorbed. Take `R=8.31J mol e^(-1) K^(-1)`.

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