Saved Bookmarks
| 1. |
A graph between the square of the velocity of a particle and the distance(s) moved is shown in figure. The acceleration of the particle in kilometers per hour square is:- |
|
Answer» 2250 `a=(v^(2)-u^(2))/(2S)=((900)-(4600))/(2xx0.6)=-(3700)/(1.2)` `=-3084 km//hr^(2)` |
|