1.

A graph between the square of the velocity of a particle and the distance(s) moved is shown in figure. The acceleration of the particle in kilometers per hour square is:-

Answer»

2250
3084
-2250
-3084

Solution :`V^(2)=U^(2)+2as`
`a=(v^(2)-u^(2))/(2S)=((900)-(4600))/(2xx0.6)=-(3700)/(1.2)`
`=-3084 km//hr^(2)`


Discussion

No Comment Found

Related InterviewSolutions