1.

A graph plotted between log t_(50%) vs log concentration in a straight line. What conclusion can you draw from this graph?

Answer»

N= 1, `t_(1//2)= t/(x xx a)`
`n=2, t_(1//2) = 1/a`
`n=1, t_(1//2)= 0.693/k`
none of these

Solution :C) `t_(1//2) propto a^(1-n) = k(a)^(1-n)`
log `t_(1//2) = log k + (1-n) log a`
The graph is EXPECTED to be a straight line.
Therefore, SLOPE 1-n =0 or n=1


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