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A ground receiving station is receiving a signal at 6MHz transmitted from a ground transmitter at a height of 500m located at a distance of 100km. If radius of earth is 6.4xx10^(6)m, maxim um number density of electron in ionosphere is 10^(12)m^(-3). the signal is coming via: |
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Answer» ground wave `d=sqrt(2Rh)=sqrt(2xx(6.4xx10^(6))xx300)=80xx10^(3)m=80km` Since the distance between transm itter and receiver is 100km, HENCE for the GIVEN frequency signal of6 MHz. the propagation is not possible via space propagation. for sky wave propagation the critical frequency. `v_(C)=9(N_("MAX"))^(1//2)=9xx(10^(12))^(1//2)=9xx10^(6)Hz=9MHz` Since 6 MHz `lt9 MHz`. so the propagation of signal of frequency 6 MHzis possible via sky wave. |
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