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InterviewSolution
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A group consists of 12 persons, of which 3 are extremely patient, other 6 are extremely honest and rest are extremely kind. A person the group is selected at random. Assuming that each persons is equally likely to be selected, find the probability of selecting a person who is(i) Extremely patient,(ii) Extremely kind or honestwhich of the above values did you prefer more ? |
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Answer» The total number of persons = 12. The number of persons who are extremely patient = 3. The number of persons who are extremely kind = 12 - 3 - 6 = 3. (i) P(selecting a person who is extremely patient) = \(\frac{number\, of \,favorable\,outcomes}{number\,of \,all\,possible\,outcomes}\) = \(\frac{3}{12}\) = \(\frac{1}{4}\) Thus, the probability of selecting a person who is extremely patient is \(\frac{1}{4}\). (ii) P(selecting a person who is extremely kind of honest) = \(\frac{number\, of \,favorable\,outcomes}{number\,of \,all\,possible\,outcomes}\) = \(\frac{6+3}{12}\) = \(\frac{9}{12}\)= \(\frac{3}{4}\) Thus, the probability of selecting persons who is extremely kind or honest is \(\frac{3}{4}\). from the three given values, we prefer honesty more. |
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