InterviewSolution
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InterviewSolution
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A gun is firing bullets with velocity `v_0` by rotating it through `360^@` in the horizontal plane. The maximum area covered by the bullets isA. `pi((u^(2))/g)^(2)`B. `pi((u^(2))/(2g))^(2)`C. `pi(u/g)^(2)`D. `pi(u/(2g))^(2)` |
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Answer» Correct Answer - a `R=(u^(2)sin 2 theta)/g` Range R is maximum when ` sin 2 theta=1` `R_(max)=(u^(2))/g` Maximum area coverted `=pi(R_(max))^(2)=pi((u^(2))/g)^(2)` |
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