1.

A gun weighing 10 kg fires a bullet of 30g with avelocity of 330 m/s. With what velocity does thegun recoil? What is the combined momentum ofgun and bullet before firing and after firing?

Answer»

Momentum of the bullet equals the momentum of the gun.

Momentum equals to :

Mass × Velocity

We substitute into the formulae and get :

0.03 × 330 = 10 × V

9.9 = 10V

V = 0.99 m/s

Momentum before firing is zero since both the gun and the bullet are at rest and their velocities are zero.

Momentum after firing is equal to momentum of the gun plus the momentum of the bullet which are equal and opposite.

This is therefore :

330 × 0.03 × 2 = 19.8Kgm/s

you copy pasted it from brainy website



Discussion

No Comment Found

Related InterviewSolutions