Saved Bookmarks
| 1. |
A gun weighing 100 kg is used to fire an iron ball weigh ing 1 kg horizontally from a cliff of height 500 m above the ground. The ball falls 400 m away from the bottom of the cliff. What is the recoil velocity of the gun? (Take g =10 ms^(-2)) |
|
Answer» `0.8 MS^(-1)`  `:.t^(2)=(2h)/(g)=(2xx500)/(10)` `t=10 SEC` Also `x=ut` `:.u=(x)/(t)=(400)/(10)` `=40 m sec^(-1)` Now recoil velocity `V=(mu)/(M)` `V=(1xx40)/(100)=0.4 ms^(-1)` Hence (b) is the right CHOICE |
|