1.

A gyromagnetic ratio of the electron revolving in a circular orbit of hydrogen atoms is 8.8xx10^(10) kg^(-1)given charge of the electron =1.6 xx10^(-19) c

Answer»

`1xx10^(-19)c`
`0.1 xx10^(-29)` kg
`1.1 xx10^(-29) kg`
`1//11 xx10^(-29) kg`

Solution :We know that
Magnetic moment M=iA
here `i=(ev)/(2pir)`
`M=(evr)/(2)`

and ANGULARMOMENTUM
divindingeq (ii) EQ (ii) we get
`(M)/( L)=(e )/(2m)`
where M/L =GYROMAGNETICRATIO
GIVEN
`M//L=8.8xx10^(10) c//kg`
`e=1.6xx10^(-19)C`
`=8/88xx10^(-29)`
`=1/11xx10^(-29) kg`


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