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A(h,-6),B(2,3) and C(-6,k) are the coordinates of vertices of a triangle whose centroid is G(1,5). Find h and k. |
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Answer» A(h,-6) , B (2,3),C(-6,k) and G(1,5) . Suppose A has coordintes ` (X_(1),y_(1)) ` , B has coodintes ` (X_(2),y_(2))` C has coordinates `(X_(3) ,y_(3))` and Gn has coordinates (x,y). Here , `x_(1) = h,y_(1) = - 6, x_(2) = 2 , y_(2) = 3 , x_(3) = - 6,y_(3) = k , x = 1` and y=5. By centroid formula , ` x= (x_(1) + x_(2) + x_(3))/(3)` `therefore 1 = (h + 2+ (-6))/(3)` ` therefore 3 = h-4` ` therefore = 3+ 4 ` ` therefore h = 7` ` y=(y_(1) + y_(2) + y_(3))/(3) ` ` therefore 5 = (-6 + 3 + k)/(3)` ` therefore 15 = - 3 + k` ` therefore k = 15+ 3 ` ` therefore k = 18` ` h = 7 ad kk = 18` . |
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