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A half cell is prepared by `K_(2)Cr_(2)O_(7)` in a buffer solutoin of pH = 1. Concentration of `K_(2)Cr_(2)O_(7)` is 1 M. To 3 litre of this solution 570 gm of `SnCl_(2)` is added which is oxidised completely to `SnCl_(4)` Given : `E_(Cr_(2)O_(7)^(-2)//Cr^(+3),H^(+))^(@)=1.33V,(2.303)/(F)RT=0.06`, Atomic of mass `Sn=119 , E_(Sn^(+4)//Sn^(+2))^(@)=0.15` Number of moles of `Cr^(+3)` formed areA. 2B. 6C. 4D. 3 |
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Answer» Correct Answer - A `40.K_(2)Cr_(2)O_(7)+3SnCl_(2)+H^(+)rarr SnCl_(4)+2Cr+3` mole of `SnCl_(2)=3 " " therefore` mole of `Cr^(+3)=2` |
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