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A harmonic oscillation of force constant `4xx10^(6) Nm^(-1)` and amplitude 0.01 m has total energy 240 J. What is maximum kinetic energy and minimum potential energy? |
Answer» `k=4 xx 10^(6)N//m , A=0.01m`, Total energy =240 J minimum potential energy =total energy -maximum kinetic energy=40J | |