1.

A heat engine works on a carnot cycle with a heat sink of 27^(@)C. The efficiency is 10%. The temperature of source is

Answer»

270K
30K
`60^(@)C`
`30^(@)C`

Solution :`0.1=1-(300)/(T_(1))`
`(300)/(T_(1))=0.9`
`T_(1)=(3000)/(9)=333K`
`t_(1)=333-273`
`=60^(@)C`.


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