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A heat flux of 4000 J/s is to be passed through a copper rod of length 10 cm and area of cross section `100cm^2`. The thermal conductivity of copper is `400W//m//^(@)C` The two ends of this rod must be kept at a temperature difference ofA. `1^@C`B. `10^@C`C. `100^@C`D. `1000^@C`

Answer» Correct Answer - C
From `(dQ)/(dt)=(KaDeltatheta)/(l)`
`implies Delta theta=(l)/(KxxA)xx(dQ)/(dt)=(0.1)/(400xx(100xx10^-4))xx4000=100^@C`


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