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A heated object (at time `t=0` and temperature `T=T_(0))` is taken out of the oven to cool and placed on a table near an open window Write an expression for its temperature as function of time `T` where `T_(s)` is the surrounding temperature .A. `T=T_(s)-(T_(0)+T_(s))e^(-kt)`B. `T=T_(s)+(T_(0)+T_(s))e^(-kt)`C. `T=T_(s)+(T_(0)-T_(s))e^(-kt)`D. `T=T_(s)-(T_(0)-T_(s))e^(-kt)` |
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Answer» Correct Answer - C `(d theta)/(dt) =-K (T -T_(s))` `underset(T_(0))overset(T)int(d theta)/(T -T_(s)) = -K underset(0)overset(t)intdt log ((T-T_(s))/(T_(0)-T_(s)))=-Kt+C` . |
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