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A slab of stone area `3600 cm^(2)` and thickness `10cm` is exposed on the lower surface to steam at `100^(@)C` A block of ice at `0^(@)C` rest on upper surface of the slab. In one hour `4.8kg` of ice is melted. The thermal conductivity of the stone in `Js^(-1)m^(-1)k^(-1)` is (latent heat of ice `=3.36 xx 10^(5) J//Kg` .A. `12.0`B. `10.5`C. `1.02`D. `1.24` |
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Answer» Correct Answer - D `(mL)/(t)=(KADeltatheta)/(X)` |
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