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| 1. |
A heater coil is cut into two equal parts and only one part is now used in the heater . What is the percentage of increase or decrease in the rate f productu=ion of heat ? |
| Answer» Solution :In both case ,the potential differnces between the two ends of the coil (V) are same . So , rate of PRODUCTION of HEAT `prop(V^(2))/(R)` . When the oil is cut into two equal parts , the value ofR becomes half . So ,rate of production of heatbecomes double , i.e ., this rate increases by 100 % | |