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A heavy mass M resting on the ground is connected to a lighter mass m through a light inextensible string passing over an ideal pulley. The string connected to mass M is loose. Let lighter mass m be allowed to fall freely through a height h such that the string becomes taut. If t is the time from this instant onward when the heavier mass again makes contact with the ground and Delta E is change in kinetic energy then |
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Answer» `t=(2m)/(M+m)SQRT((2h)/(g))` |
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