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A heavy nucleus P of mass number 240 and binding energy 7.6 MeV per nucleon splits in to two nuclei Q and R of mass numbers 110, 130 and binding energy per nucleon 8.5 MeV and 8.4 MeV, respectively. Calculate the energy released in the fission. |
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Answer» Solution :As per QUESTION total binding ENERGY of heavy nucleus =`240xx7.6=1824` MeV Total binding energy of nucleus Q =` 110 xx 8.5 = 935` MeV and total binding energy of nucleus R = `130 xx8.4 = 1092` MeV `:.` Total binding energy of splitted nuclei Q and R = 935 + 1092 = 2027 Mev `:.` Energy RELEASED in the fission = 2027 -1824 = 203 MeV |
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