1.

A heavy nucleus X of mass number 240 and binding energy per nucleon 7.6 MeV is split into two fragments Y and Z of mass numbers 110 and 130. The binding energy of nucleons in Y and Z is 8.5MeV per nucleon. Calculate the energy Q released per fission in MeV.

Answer» The nuclear reaction is
`X^(240)toY^(110)+Z^(130)+Q`
As per the given data,
`Q=110xx8.5+130xx8.5-240xx7.6`
`=240(0.9)MeV=216MeV`
Energy released /fission `=216MeV`


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