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Energy of an electron in an excited hydrogen atom is `-3.4eV`. Its angualr momentum will be: `h = 6.626 xx 10^(-34) J-s`. |
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Answer» Correct Answer - `2.11xx10^(-34)Js` `E=(-13.6)/(n^(2))=-3.4eV :. n=2` `:.` Angular momentum of electron `=(nh)/(2pi)=2h//2pi=h/pi=(6.626xx10^(-34))/3.14` `2.11xx10^(-34)J-s` |
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