A helicopter is moving in upward direction with speed of 10 m/s. If the length of the helicopter is 10 m and the horizontal component of magnetic field of earth is 1.5 xx 10^(-3) "Wb"/ m^2 then the induced emf produced across the foremost (nose) and end part (tail) of the helicopter will be ____

A helicopter is moving in upward direction with speed of 10 m/s. If th

1.	A helicopter is moving in upward direction with speed of 10 m/s. If the length of the helicopter is 10 m and the horizontal component of magnetic field of earth is 1.5 xx 10^(-3) "Wb"/ m^2 then the induced emf produced across the foremost (nose) and end part (tail) of the helicopter will be ____
Answer» 0.15 V 125 V 130 V 5 V Solution :Induced emf `epsilon=Hlv sin theta` `=1.5xx10^(-3)xx10xx10xx"sin"pi/2` `therefore epsilon` =0.15V

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A helicopter is moving in upward direction with speed of 10 m/s. If the length of the helicopter is 10 m and the horizontal component of magnetic field of earth is 1.5 xx 10^(-3) "Wb"/ m^2 then the induced emf produced across the foremost (nose) and end part (tail) of the helicopter will be ____

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