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A hemispherical bowl made of brass has inner diameter 10.5 cm. What is the cost of tin-plating it onthe inside at the rate of Rs.7 per 100 sq.cm.?10 |
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Answer» Answer: 48.49 rupees Step-by-step EXPLANATION: Tin plating is over the inner surface area of bowl. Curved surface area= 2pi r² = 2 × 10.5² × pi = 220.5 pi cm² TOTAL cost of 220.5 pi cm² = 7/100 × 220.5 pi = 4849.048/100 = 48.49 rupees |
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