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A hole is drilled half way to the centre of the Earth. A body is dropped into the hole. How much will it weigh at the bottom of the hole if the weight fo the body on the Earth's surface is 350 N? |
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Answer» Solution :GIVEN : WEIGHT of the BODY on Earth's surface, W = mg = 350 N. Body is thrown at depth, Depth, `d=(R )/(2)` Where R is the radius of the earth. At depth d, the acceleration due to gravity is given by, `g_(d)=G[1-(d)/(R )]` `therefore ` Weight of the body at depth d is `W_(d)=mg_(d)=mg[1-(d)/(R)]` `=350 [1-(R//2)/(R)]` `=350 xx (1)/(2)` ` =175 N.` |
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