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A hollow conducting sphere of inner radius R and outer radius 2R has resistivity 'rho' a function of the distance 'r' from the centre of the sphere: rho=kr^(2)//R. The inner and outer surfaces are painted with a perfectly conducting 'paint' and a potential difference DeltaV is applied between the two surfaces. Then, as 'r' increases from R to 2R, the electric field inside the sphere |
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Answer» increases `E=(KR^(2))/R i/(pir^(2))` `E-(KI)/(pir)` |
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