Saved Bookmarks
| 1. |
A hollow copper cylinder is of inner radius 4cm and outer radius 5cm. Now hollow portion is completely filled with suitable copper wires. Find percentage change in its electric resistance. |
|
Answer» Solution :`R_(1)=(rhol)/(pi(5^(2)-4^(2)))=(rhol)/(9pi)=(k)/(9)` FINAL Resistance `R_(2)=(rhol)/(pi(5^(2)))=(rhol)/(25pi)=(k)/(25)` Percentage of change `=(R_(2)-_(1))/(R_(1))XX100` |
|