1.

A hollow cylinder has mass M, outside radius R2 and inside radius R1. Its moment of inertia about anaxis parallel to its symmetry axis and tangential to the outer surface is equal to(A) 쓸 (R22 + R?)(B) 블 (R22-R12)(C)블(R2 + Rıf(D)쓸(3R22 + R12)4

Answer»

The total energy in the system is given by

T = 1/2 m2 Vo^2 + 1/2 m1 Vo^2 + 1/2 I wo^2= 1/2 m2 Vf^2 + 1/2 m1 Vf^2 + 1/2 I wf^2 - m1gd + uk m2g d

where Vo,Vf are the initial and final velocity of the blocks, wo/wf are the initial and finalangular velocityof the pulley, I is themoment of inertiaof the pulley. w is related to V as

Vo = R2 wo and Vf = R2 wf.

Also, the moment of inertia is given by

I = 1/2 m (R2^2 + R1^2)



Discussion

No Comment Found

Related InterviewSolutions