1.

A hollow pipe of length 0.8 m is closed at one end. At its open end a 0.5 m long uniform string as vibrating in its second harmonic and it resonates with the fundamental frequency of te pipe. If the tension in the wire is 50 N and the speed of sound is 320 ms^(-1) the mass of the string is :

Answer»

5 grams
10 grams
20 grams
40 grams

SOLUTION :Fundamental frequency of pipe is
given by `f_(2) = v//4l_(2) ( v = 320 ms^(-1))`
` f_(1) = sqrt(T//mu)l_(1) ` Both are same `f_(1)= f_(2) `
`rArr "" m = T l_(1) // 2500 ` = 10g
So correct choice is (B).


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