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A homogeneous solid cylinder of length L(LltH/2), cross-sectional area A/5 is immersed such that it floats with its axis vertical at the liquid-liquid interface with length L/4 in the denser liquid as shown in the figure. The lower density liquid is open to atmosphere having pressure `P_0`. Then density D of solid is given by A. (a) `5/4d`B. (b) `4/5d`C. (c) `4d`D. (d) `d/5` |
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Answer» Correct Answer - A Weight of cylinder=Upthrust due to upper liquid+Upthrust due to lower liquid. `D(A/5xxLxxg)=d(A/5)(3/4L)g+2d(A/5)(L/4)xxg` `:.D=(5d)/(4)` |
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