1.

A homogenous disc of mass 2 kg and radius 10 cm is rotating about its axis with an angular velocity of 4 rad s^(-1). The angular momentum of the disc is :

Answer»

1 KG `ms^(-1)`
0.6 kg `ms^(-1)`
1.2 kg `ms^(-1)`
None of these

Solution :`I=(1)/(2)mr^(2)=(1)/(2)xx2(0.1)^(2)=0.01kgm^(2)`
Now ANGULAR momentum
`L=Iomega=0.01xx4=0.04kgm^(2)s^(-1)`


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