A hoop of radius r and mass m rotating with an angular velocity omega_(0) is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the loop when it ceases to slip?

A hoop of radius r and mass m rotating with an angular velocity omega_

1.	A hoop of radius r and mass m rotating with an angular velocity omega_(0) is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the loop when it ceases to slip?
Answer» `(romega_(0))/(3)` `(romega_(0))/(2)` `romega_(0)` `(romega_(0))/(4)` Solution :From conservation of ANGULAR momentum about any fix point on the surface `mr^(2)omega_(0)=2mr^(2)OMEGA` `therefore omega=(omega_(0))/(2)` `therefore V_(CM)=(omega_(0)r)/(2)`

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A hoop of radius r and mass m rotating with an angular velocity omega_(0) is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the loop when it ceases to slip?

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