1.

A horizontal platform executes up and down S.H.M. about amean position. Its period is 2pi s. A massm is resting on the platform, what is the greatest value of amplitude so that the mass 'm' may notleave the platform ?

Answer»

4.9 m
9.8 m
2.25 m
19.6 m

Solution :For mass not to leave the platform, the maximum acceleration `a_("max")=g`.
`:.""OMEGA^(2)r=g`
`(4PI^(2))/(T^(2)).r=g`
`r=g XX(T^(2))/(4pi^(2))`
Since `T=2pi s`.
`:.""r=gxx(4pi^(2))/(4pi^(2))=9.8" m"`
Hencecorrect CHOICE is (b).


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