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A horizontal power line carries a current of 90A in east to west direction. What is the magnitude and direction of the magnetic field due to the current 1.5m below the line? |
Answer» Solution : According to FORMULA, `B=(mu_(0)I)/(2pir)` `thereforeB=((4pixx10^(-7))(90))/((2pi)(1.5))` `thereforeB=1.2xx10^(-5)T` (TOWARDS south from point P, as shown in the figure according to right HAND THUMB rule). |
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