1.

A horizontal power line carries a current of 90A in east to west direction. What is the magnitude and direction of the magnetic field due to the current 1.5m below the line?

Answer»

Solution :
According to FORMULA,
`B=(mu_(0)I)/(2pir)`
`thereforeB=((4pixx10^(-7))(90))/((2pi)(1.5))`
`thereforeB=1.2xx10^(-5)T`
(TOWARDS south from point P, as shown in the figure according to right HAND THUMB rule).


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