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A horizontal rod `0.2 m` long is mounted on a balnce and carries a current. At the location of the rod a uniform horizontal magnetic field has magnitude `0.067 T` and direction perpendicular to the rod. The magnetic force on the rod is measured by the balance and is found to be `0.13N`. What is the current? |
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Answer» `F=ilB sin90^@` `:. =F/(lB)=0.13/(0.2xx0.067)` `=9.7A` |
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