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a. How will you convert an alkyl halide to a primary amine whose molecule has one carbon atom more than the used alkyl halide molecule? b. Why are amines more basic than the comparable alcohols. |
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Answer» Solution :a. `underset("CHLOROMETHANE")(CH_(3)Cl)+KCNtounderset("Ethananitrile")(CH_(3)C-=N) underset(4[H])overset(Na//C_(2)H_(5)OH)(to) underset("Ethanamine")(CH_(3)CH_(2)NH_(2))` B. Due less electronegativity of oxygen atom as compared to nitrogen, AMINES are more basic than alcohols. |
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