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(a) How will you distinguish between Pentan-2-one and Pentan-3-one with the help of Iodoform test ? (b) How will you bring about following conversions ? (i) Benzoic acid to m-Nitrobenzyl alcohol. (ii) Benzaldehyde to Benzophenone. (iii) Benzoic acid to Benzamide. |
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Answer» Solution :(a) Pentan-2-one gives iodoform TEST i.e. YELLOW ppt on WARMING with `I_(2)` and NaOH but pentan-3-one does not. `CH_(3)-overset(O)overset(||)C-CH_(2)CH_(2)-CH_(3)+3I_(2)+4NaOH overset(Delta)to CH_(3)CH_(2)CH_(2)COONa+underset("Yellow ppt.")(CHI_(3))+3NaI+3H_(2)O` `CH_(3)-CH_(2)-overset(O)overset(||)C-CH_(2)-CH_(3)+I_(2)+NaOH overset(Delta)to "No reaction"` (b)
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