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A hydrocarbon contains 10.5 gm carbon and 1 gm hydrogen. Its 2.4 gm has 1 L volume at 1 atm and 127^(@)C, hydrocarbon is

Answer»

`C_(6)H_(7)`
`C_(6)H_(8)`
`C_(5)H_(6)`
None of these

Solution :`C = 10.5 GM = (10.5)/(12) mol = 0.87 mol`
`H = 1 gm = (1)/(1) = 1MOL`
`:. (C_(0.87)H_(1))_(7) = C_(6.09)H_(7) = C_(6)H_(7)`
`PV = nRT`, `PV = (w)/(m)RT`
`1 XX 1 = (2.4)/(m) xx 0.082 xx 400`
`m = 2.4 xx 0.082 xx 400 = 78.42 = 79`.


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