1.

A hydrocarbon has density 1.25 gL^(-1)at STP . The hydrocarbonis

Answer»

`C_(2)H_(4)`
`C_(2)H_(2)`
`C_(2)H_(6)`
`C_(3)H_(6)`

SOLUTION :1L of hydrocarbon at STP weighs `= 1.25 g`
`22.4 L` of hydrocarbon at STP weigh
`= 1.25 xx 22.4 = 5/4 xx 22.4 = 28.0 g mol^(-1)`
Hydrocarbon will be `C_(2)H_(4) = 2xx 12 + 4 = 28 g mol^(-1)`
(B) , (c ) and (d) are not possible.


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