A hydrocarbon 'P' having molecular formula C_(8)H_(10) can form only three monochloroderivative. 'P' on oxidation with KMnO_(4) yields a compound, which on heating with aq. NH_(3) yields 'Q'. 'Q' on treatment with NaOH followed by NaOCl yields a salt which on acidification yields with (NaNO_(2)+HCl) and then with base to give dipolar ion 'S' which readily losses two gases two give an intermediate 'T' is finally converted into hydrocarbon 'U' on dimerisation. degree of unsaturation in the hydrocarbon 'U' will be:

A hydrocarbon 'P' having molecular formula C_(8)H_(10) can form only t

1.	A hydrocarbon 'P' having molecular formula C_(8)H_(10) can form only three monochloroderivative. 'P' on oxidation with KMnO_(4) yields a compound, which on heating with aq. NH_(3) yields 'Q'. 'Q' on treatment with NaOH followed by NaOCl yields a salt which on acidification yields with (NaNO_(2)+HCl) and then with base to give dipolar ion 'S' which readily losses two gases two give an intermediate 'T' is finally converted into hydrocarbon 'U' on dimerisation. degree of unsaturation in the hydrocarbon 'U' will be:
Answer» ANSWER :9